Write a C, C++ program to check whether a given number is perfect or not. We have to write a program to check whether a input number is perfect.
Perfect Number
A perfect number, is a positive integer that is equal to the sum of its proper divisors.
For example - 6 is a perfect number.
6 = 1 + 2 + 3 (1,2,3 is it's factors).
Similarly 28 is a perfect number.
28 = 1 + 2 + 4 + 7 + 14
Let's take another example of 12. Factors of 12 is 1, 2, 3, 4, 6.
1 + 2 + 3+ 4 + 6 = 16. So we can conclude that 12 is not a perfect number.
Print factors of a number
C, C++ Interview Questions
Print prime numbers between 1 to 100
Enter number : 6
6 is a perfect number
Enter number : 23
23 is not a perfect number
Perfect Number
A perfect number, is a positive integer that is equal to the sum of its proper divisors.
For example - 6 is a perfect number.
6 = 1 + 2 + 3 (1,2,3 is it's factors).
Similarly 28 is a perfect number.
28 = 1 + 2 + 4 + 7 + 14
Let's take another example of 12. Factors of 12 is 1, 2, 3, 4, 6.
1 + 2 + 3+ 4 + 6 = 16. So we can conclude that 12 is not a perfect number.
Print factors of a number
C, C++ Interview Questions
Print prime numbers between 1 to 100
Perfect Number Program in C
#include <stdio.h> int main(void) { int num, i=1, sum=0; printf("Enter number \n"); scanf("%d",&num); /* Check if entered number is greater than zero. */ if( num > 0){ while(i < num){ if(num % i==0){ sum = sum + i; } i++; } /* If entered number is equal to it's proper divisiors. */ if(sum == num){ printf("\n %d is a perfect number",i); } else { printf("\n %d is not a perfect number",i); } } else { printf("Perfect number should be greater than zero"); } return 0; }Output :
Enter number : 6
6 is a perfect number
Enter number : 23
23 is not a perfect number
Perfect Number Program in C++
#include <iostream> using namespace std; int main() { int num, sum = 0; cout << " Enter a number to check whether it's a perfect or not \n"; cin >> num; for (int i = 1; i < num; i++) { if (num % i == 0) { sum = sum + i; } } if ( sum == num) { cout << num << " is a Perfect number"; } else { cout << num << " is not a Perfect number"; } return 0; }
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