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### Program to Check Whether a Number is Even or Odd - C, C++ Code

Write a Program to check whether a number is even or odd. Given an input number, we have to write a code to check whether an input number is even or odd.

Before solving this problem, let's first understand what is even or odd number?

#### Even number

Any integer that can be perfectly divisible by 2 is an even number.

For example - 2, 4, 6, 8, 10 etc.

#### Odd Number

An odd number is a number that is not divisible by 2.

For example - 3, 5, 7 etc.

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Algorithm to check whether a number is even or odd number

1. Declare a variable num (You can declare any variable).

2. Take an input number from user and store this value in num variable.

3. Check whether a number is perfectly divisible by 2 .If it is divisible by 2 then it's a even number otherwise it is an odd number.

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## C Program to Check whether a Number is Even or Odd

```#include <stdio.h>

void main()
{

int num;

printf("Enter an integer value");
scanf("%d", &num);

/* If a number is perfectly
divisible by 2 then it's an even number*/

if(num % 2 == 0){
printf(" \n %d is an even number ", num);
} else {
printf(" \n %d is an odd number ", num);
}

}

```

Output :

Enter an integer value  : 10

10 is an even number

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## C++ Program to Check whether a Number is Even or Odd

```#include <iostream>
using namespace std;

int main() {

int num;

cout << "Enter an integer value\n";
cin >> num;

if(num % 2 == 0){
cout << " \n Entered number is an even number ";
} else {
cout << " \n Entered number is an odd number ";
}

return 0;
}
```

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