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Program to Check Whether a Number is Even or Odd - C, C++ Code

Write a Program to check whether a number is even or odd. Given an input number, we have to write a code to check whether an input number is even or odd.

Before solving this problem, let's first understand what is even or odd number?


Even number


Any integer that can be perfectly divisible by 2 is an even number. 

For example - 2, 4, 6, 8, 10 etc.


Odd Number


An odd number is a number that is not divisible by 2.

For example - 3, 5, 7 etc.



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Algorithm to check whether a number is even or odd number

1. Declare a variable num (You can declare any variable).


2. Take an input number from user and store this value in num variable.


3. Check whether a number is perfectly divisible by 2 .If it is divisible by 2 then it's a even number otherwise it is an odd number.


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C Program to Check whether a number is even or odd



C Program to Check whether a Number is Even or Odd


#include <stdio.h>

void main()
{
 
   int num; 
 
   printf("Enter an integer value");
   scanf("%d", &num);
 
   /* If a number is perfectly
      divisible by 2 then it's an even number*/

   if(num % 2 == 0){  
      printf(" \n %d is an even number ", num);
   } else {
      printf(" \n %d is an odd number ", num);
   }

}



Output :

Enter an integer value  : 10

10 is an even number

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C++ Program to Check whether a Number is Even or Odd


#include <iostream>
using namespace std;

int main() {
 
   int num; 
 
   cout << "Enter an integer value\n";
   cin >> num;
 
   if(num % 2 == 0){  
      cout << " \n Entered number is an even number ";
   } else {
      cout << " \n Entered number is an odd number ";
   }
   
 return 0;
}




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