C, C++ Program to Check Whether a Number is Even or Odd |

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**Algorithm to check even or odd number**

**1. Declare a variable num (You can declare any variable).**

2. Take a input from user and store this value in num variable.

**3. Check whether a number is perfectly divisible by 2 .If it is divisible by 2 then it's a even number otherwise it is an odd number.**

## C Program to Check whether a Input Number is Even or Odd

#include <stdio.h> void main() { int num; printf("Enter an integer value"); scanf("%d", &num); /* If number is perfectly divisible by 2 */ if(num%2 == 0){ printf(" \n Entered number is an even number "); } else { printf(" \n Entered number is an odd number "); } }

**Output :**

**Enter an integer value : 10**

Entered number is an even number

## C++ Program to Check whether a Input Number is Even or Odd

#include <iostream> using namespace std; int main() { int num; cout << "Enter an integer value\n"; cin >> num; if(num % 2 == 0){ cout << " \n Entered number is an even number "; } else { cout << " \n Entered number is an odd number "; } return 0; }

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