Logic of a Program
1. Take input from user.
2. Run a loop to check each element of an array. If the remainder of a number is zero by
the division of 2 then It's a even number else it's a odd number.
// Check whether the Remainder of a number is zero by division of 2
if(arr[i]%2==0){
print even no.
} else {
print odd no.
}
Program to Print Odd and Even Numbers of an Array
// Program
#include <stdio.h>
void main()
{
// Declare variables.
int arr[100],i,n;
printf("How many elements you want to enter");
scanf("%d",&n);
printf("Enter the elements in an array");
// Taking the input from user
for(i=0;i<n;i++){
scanf("%d",&arr[i]);
}
// Logic of even and odd numbers
for(i=0;i<n;i++){
if(arr[i]%2==0){
printf("Even number is %d\n",arr[i]);
}else{
printf("odd number is %d\n",arr[i]);
}
}
}
Questions Related to Array
Problem on Linked List
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