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C Program to Check whether a Character is Vowel or Consonant

Write a c program to check whether a character is vowel or consonant. In this program, we take an input character from a user and our code will check whether an input character is vowel or consonant.

Before start writing code, let's first understand what is vowel and consonant?

What is vowel and consonant?

In english, Alphabet a, e, i, o, u is called vowel and rest of the alphabets is called consonant.

How to Check whether a Character is Vowel or Consonant 

 1. Take an input character from a user. 

 2. Compare input character with a, e, i, o, u, A, E, I, O, U. If it matches with any of them then it's a vowel otherwise it's a consonant.

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C Program to Check whether a Character is Vowel or Consonant


C Program to Check Whether a Character is Vowel or Consonant


In this example, we take an input alphabet from a user and then compare with a, e, i, o, u (upper and lower case both). If input character is matches then it's a vowel otherwise it's a consonant.

#include <stdio.h>

int main(void) {
 
  //Declar char
  char alpha;

  // Take a input character from a user

  printf(" Enter an alphabet\n");
  scanf("%c", &alpha);

  //Compare

  if ( alpha == 'a' || alpha == 'A' 
       || alpha == 'e' || alpha == 'E' 
          || alpha == 'i' || alpha == 'I' 
       || alpha =='o' || alpha=='O' 
           || alpha == 'u' || alpha == 'U') {

      printf("%c is a vowel", alpha);
  } else {
      printf("%c is a consonant", alpha);
  }
       
 return 0;

}



Output :

Enter an alphabet : a

a is a vowel

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C Program to Check Whether a Character is Vowel or Consonant using Switch Statement


In this example, we use switch statement to check whether an input alphabet is vowel or consonant. The logic is same. In this case, we solve this problem in another way using switch statement.


#include <stdio.h>

int main(void) {
 
    
      char alpha;

      // Take an input character from a user.

      printf(" Enter an alphabet \n");
      scanf("%c", &alpha);

      switch(alpha) {
              
          case 'a':
          case 'A':
          case 'e':
          case 'E':
          case 'i':
          case 'I':
          case 'o':
          case 'O':
          case 'u':
          case 'U':
             printf("%c  is a vowel", alpha);
             break;
          default:
             printf("%c  is not a vowel", alpha);
              
      }
      
     return 0;
}


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3 comments:

  1. Thank you for your help.

    ReplyDelete
  2. have tried the same program on visual studio ultimate 2012 but have found two errors.
    1. on the opening brace after the "if (condition)" it says Error: expected an expression.
    2. on the last brace that closes the whole code the error is 'expected a ')'

    ReplyDelete
  3. This comment has been removed by a blog administrator.

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